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b. 15
c. 76
d. 11
e. 14
b) 4 + [3+(2-1)+7] = 4 + [3+(1)+7] = 4 + [11] = 15
c) [5-(2-1)+72] = [5-(1)+72] = 76
d) 3+{10-[4-(3-1)]} = 3+{10-[4-2]} = 3+{10-2} = 3+8= 11
e) {[(4+1)-(5-3)+2]+9} = {[(5)-(2)+2]+9}= 5 + 9 = 14
Nota: se resuelven primero las operaciones dentro de ( ), luego las de [ ] y por último las de { }. En ese orden.