Respuesta:
1 caso:
5×a-3×b+5= (5×2)-(3×4)+5= 10-12+5=3
(a+b)²×3+4= (2+4)²×3+4 (2+4)² es una igualdad notable 4+16+16(sale de 2²+4²+2*2*4)×3+4= 36×3+4=108+4= 112
2 caso
5×3-3×6+5=6-18+5=-7
(3+6)²×3+4= 9+36+36×3+4= 81×3+4= 243+4= 247
3 caso
5*6-3*9+5=30-27+5=8
(6+9)²*3+4=36+81+108*3+4= 225*3+4=675+4=679
4 caso
5*(-3)-3*(-6)+5=-15+18+5=8
(-3-6)²*3+4= (9+36-36)*2+4= 9*3+4=27+4=31
espero que te aclares :)
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Respuesta:
1 caso:
5×a-3×b+5= (5×2)-(3×4)+5= 10-12+5=3
(a+b)²×3+4= (2+4)²×3+4 (2+4)² es una igualdad notable 4+16+16(sale de 2²+4²+2*2*4)×3+4= 36×3+4=108+4= 112
2 caso
5×3-3×6+5=6-18+5=-7
(3+6)²×3+4= 9+36+36×3+4= 81×3+4= 243+4= 247
3 caso
5*6-3*9+5=30-27+5=8
(6+9)²*3+4=36+81+108*3+4= 225*3+4=675+4=679
4 caso
5*(-3)-3*(-6)+5=-15+18+5=8
(-3-6)²*3+4= (9+36-36)*2+4= 9*3+4=27+4=31
espero que te aclares :)