Area de un cono
A = π.r.g + π.r²
reemplazamos
A = π.(5 cm).(5√17 cm) + π.(5 cm)²
A = 25π√17 cm² + 25π cm²
A =25π(√17 + 1) cm²
Volumen de un cono
V = 1/3.π.r².h
V = 1/3.π.(5 cm)².(20 cm)
V = 1/3.π.(25 cm²).(20 cm)
V = 500π/3 cm³
obs :
el radio es la mitad del diametro
r = d/2 => 10 cm/2 = 5 cm
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Area de un cono
A = π.r.g + π.r²
reemplazamos
A = π.(5 cm).(5√17 cm) + π.(5 cm)²
A = 25π√17 cm² + 25π cm²
A =25π(√17 + 1) cm²
Volumen de un cono
V = 1/3.π.r².h
V = 1/3.π.(5 cm)².(20 cm)
V = 1/3.π.(25 cm²).(20 cm)
V = 1/3.π.(25 cm²).(20 cm)
V = 500π/3 cm³
obs :
el radio es la mitad del diametro
r = d/2 => 10 cm/2 = 5 cm