Respuesta:
Ta = 9.47 s
Explicación:
vₐ = [tex]v_{A} =\sqrt{vi^{2} +2ad} = \sqrt{0^{2}+2(3m/s^{2})(18m) }=\sqrt{108m^{2}/s^{2} }= 10.39m/s[/tex]
[tex]v_{B} =\sqrt{vi^{2} +2ad} = \sqrt{0^{2}+2(2m/s^{2})(18m) }=\sqrt{72m^{2}/s^{2} }= 8.49m/s[/tex]
[tex]Ta = \frac{d}{V_{A} -V_{B} } = \frac{18m}{10.39m/s-8.49m/s}= \frac{18m}{1.9m/s} = 9.47s[/tex]
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Verified answer
Respuesta:
Ta = 9.47 s
Explicación:
vₐ = [tex]v_{A} =\sqrt{vi^{2} +2ad} = \sqrt{0^{2}+2(3m/s^{2})(18m) }=\sqrt{108m^{2}/s^{2} }= 10.39m/s[/tex]
[tex]v_{B} =\sqrt{vi^{2} +2ad} = \sqrt{0^{2}+2(2m/s^{2})(18m) }=\sqrt{72m^{2}/s^{2} }= 8.49m/s[/tex]
[tex]Ta = \frac{d}{V_{A} -V_{B} } = \frac{18m}{10.39m/s-8.49m/s}= \frac{18m}{1.9m/s} = 9.47s[/tex]