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solucion:
Ae=4πr²
Ae=4×π×7²
Ae=4×π×49
Ae=196π cm²
Área del Huso
Ah=4×π×r²×n/360
Ah=4×π×7²×36/360
Ah=4×π×49×36/360
Ah=7056π/360
Ah=19,6π cm²
espero que te sirva
saluods