Cada estudiante balanceara una ecuación por el método de óxido-reducción y método ion electrón • CuFeS2 + O2 --> SO2 + CuO + FeO, alguien quien me colabore por fa
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CuFeS2 + O2→ SO2 + CuO + FeO
₋₂ ₊₄
S₂ → 2S + 6 e⁻` 2 simplificar 1
₀ ₋₂
2e⁻ + O2 → O2 6 3
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₋₂ ₀ ₋₂ ₊₄
S₂ + 6 e⁻ + 3O2→ 6e⁻ + 3O2 + 2S
CuFeS2 + 3 O2 → 2 SO2 + CuO + FeO