Help ! Do wody o masie 60kg wrzucono podkowe o masie 2kg i cieple właściwym 460J Oblicz temperature końcową mieszaniny . Temperatura początkowa podkowy 400´C Powinno wyjść około 21 :/
hanecka
M₁ = 60 kg T₁ = 20 C cw₁ = 4200 J/kg * C m₂ = 2 kg T₂ = 400 C cw₂ = 460 J/kg * C Tm = ? Q₁ = Q₂ m₁*cw₁*ΔT₁ = m₂ * cw₂ * ΔT₂ m₁ * cw₁ * ( Tm - T₁ ) = m₂ * cw₂ * ( T₂ - Tm)
60 kg * 4200 J/kg * C * ( Tm - 20 C ) = 2 kg * 460 J/kg * C * ( 400 C - Tm) 252000 J/C ( Tm - 20 C ) = 920 J/C * ( 400 C - Tm) 252000 J/C * Tm - 5040000 J = 368000 J - 920 J/C *Tm 252000 J/C * Tm + 920 J/C * Tm = 368000 J + 252000 J Tm = 5408000 J / 252920 J/C Tm = 21,38 C
T₁ = 20 C
cw₁ = 4200 J/kg * C
m₂ = 2 kg
T₂ = 400 C
cw₂ = 460 J/kg * C
Tm = ?
Q₁ = Q₂
m₁*cw₁*ΔT₁ = m₂ * cw₂ * ΔT₂
m₁ * cw₁ * ( Tm - T₁ ) = m₂ * cw₂ * ( T₂ - Tm)
60 kg * 4200 J/kg * C * ( Tm - 20 C ) = 2 kg * 460 J/kg * C * ( 400 C - Tm)
252000 J/C ( Tm - 20 C ) = 920 J/C * ( 400 C - Tm)
252000 J/C * Tm - 5040000 J = 368000 J - 920 J/C *Tm
252000 J/C * Tm + 920 J/C * Tm = 368000 J + 252000 J
Tm = 5408000 J / 252920 J/C
Tm = 21,38 C