W polu jednorodnym o natezeniu 1N/C znajduje sie proton. Oblicz jaka odleglosc przebedzie on w czasie 0,01s i jaka uzyska predkosc?
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F = qE = eE
a = F/m = eE/m = (1.6*10^-19)*1/(1.67*10^-27) = 96 000 000 m/s^2
s = 0.5at^2 = 0.5*96 000 000*0.01^2 = 4800 m
v = at = 96 000 000*0.01 = 960 000 m/s