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V = 10 liter
T0= 50 C
T = 100 C
α = 4x10⁻⁵/C
dIT : V ?
dijwb :
γ = 3 x α
= 3 x 4x10⁻⁵
= 12x10⁻⁵
V = V0 (1+γ ΔT)
= 10 (1+ 12x10⁻⁵ x (100-50))
= 10 (1 + 12x10⁻⁵ x 50)
= 10 (1+ 6x10⁻³)
= 10,06 Liter