Tolong di bantu dong, kak :) sebuah lempeng persegi terbuat dari aluminium pada suhu 0°C berkurang panjang 15 cm dan lebarnya 28cm. koefisien muai linear aluminium adalah 2,4 x 10pangkat min 5/°C. Luas lempeng tersebut jika suhunya dinaikkan menjadi 100°C adalah?
sylvimeyza30
Diketahui : So = 15 cm S = 28 cm ∆T = 100 - 0 = 100°C α = 2,4 x 10⁻⁵ /°C
Ditanya : L = ?
Jawab : Ao = So x So Ao = 15 cm x 28 cm Ao = 420 cm²
β = 2 α β = 2 x 2,4 x 10⁻⁵ = 4,8 x 10⁻⁵ /°C
∆A = Ao.β.∆T ∆A = 420 x 4,8 x 10⁻⁵ x 100 ∆A = 2,016 cm²
L = 420 + 2,016 = 422,016 cm²
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Erismadewi
Dik : So = 15 cm S = 28 cm ∆T = 100 - 0 = 100°C α = 2,4 x 10⁻⁵ /°C
Dit : L =..... ?
Jawab : Ao = So x So Ao = 15 cm x 28 cm Ao = 420 cm²
β = 2 α β = 2 x 2,4 x 10⁻⁵ = 4,8 x 10⁻⁵ /°C
∆A = Ao.β.∆T ∆A = 420 x 4,8 x 10⁻⁵ x 100 ∆A = 2,016 cm²
So = 15 cm
S = 28 cm
∆T = 100 - 0 = 100°C
α = 2,4 x 10⁻⁵ /°C
Ditanya : L = ?
Jawab :
Ao = So x So
Ao = 15 cm x 28 cm
Ao = 420 cm²
β = 2 α
β = 2 x 2,4 x 10⁻⁵ = 4,8 x 10⁻⁵ /°C
∆A = Ao.β.∆T
∆A = 420 x 4,8 x 10⁻⁵ x 100
∆A = 2,016 cm²
L = 420 + 2,016 = 422,016 cm²
So = 15 cm
S = 28 cm
∆T = 100 - 0 = 100°C
α = 2,4 x 10⁻⁵ /°C
Dit : L =..... ?
Jawab :
Ao = So x So
Ao = 15 cm x 28 cm
Ao = 420 cm²
β = 2 α
β = 2 x 2,4 x 10⁻⁵ = 4,8 x 10⁻⁵ /°C
∆A = Ao.β.∆T
∆A = 420 x 4,8 x 10⁻⁵ x 100
∆A = 2,016 cm²
L = 420 + 2,016 = 422,016 cm²