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V₁ = 1 liter setara dgn= 1000 cm³
T₁ = 0°C
T₂ = 100°C
ΔV = 10 cm³
γ = 1,8*10⁻⁴/°C
Maka α = ????????
ΔV = V₁ * (γ - 3α) * ΔT
10 = 1000 * (1,8*10⁻⁴ - 3α) * (100 - 0)
α ≈ 2,67*10⁻⁵/°C
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