Materi: Listrik Statis 1. Dua buah muatan listrik masing-masing 6 × 10^-5 C dan 5 × 10^-5 C. Diletakkan pada jarak tertentu hingga menimbulkan gaya tolak menolak 5 × 10^6 N. Jika K = 9 x 10^9 Nm²/C^-², tentukan jarak dua muatan tersebut! 2. Dua buah muatan yang identik diletakkan pada jarak 12 cm satu sama lain menimbulkan gaya tolak sebesar 3,3 × 10^6 N. Jika K = 9 × 10^9 Nm²/C-². Berapa besar muatan masing-masing? . BantuDijawabYahh:) PakeCara PakeDik&Dit Tq
Nomor 1 Diketahui: k = 9 x 10⁹ Nm²/C², q₁ = 6 x 10⁻⁵ C, q₂ = 5 x 10⁻⁵ C & F = 5 x 10⁶ N Ditanyakan: r = ... Jawab: F = kq₁q₂ / r² r = √(kq₁q₂ / F) = √[(9 x 10⁹ Nm²/C²)(6 x 10⁻⁵ C)(5 x 10⁻⁵ C) / (5 x 10⁶ N)] = √[(270 x 10⁻¹ Nm²) / (5 x 10⁶ N)] = √(54 x 10⁻⁷ m²) = √(5,4 x 10⁻⁶ m²) = 0,6√15 x 10⁻³ m = 0,6√15 mm
Nomor 2 Diketahui: k = 9 x 10⁻⁹ Nm²/C², r = 12 cm & F = 3,3 x 10⁶ N Ditanyakan: q₁ = ... C dan q₂ = ... C Jawab: q₁ = q₂ = q F = kq² / r² q = r √(F / k) = (1,2 x 10⁻¹ m) √[(3,3 x 10⁶ N) / (9 x 10⁹ Nm²/C²)] = (1,2 x 10⁻¹ m) √(11/30 x 10⁻³ C²/m²) = (1,2 x 10⁻¹ m) √(11/300 x 10⁻² C²/m²) = (1,2 x 10⁻¹ m) (1/30 √33 x 10⁻¹ C/m) = 0,04√33 x 10⁻² C q₁ = q₂ = 0,04√33 x 10⁻² C
Verified answer
Nomor 1Diketahui:
k = 9 x 10⁹ Nm²/C², q₁ = 6 x 10⁻⁵ C, q₂ = 5 x 10⁻⁵ C & F = 5 x 10⁶ N
Ditanyakan:
r = ...
Jawab:
F = kq₁q₂ / r²
r = √(kq₁q₂ / F)
= √[(9 x 10⁹ Nm²/C²)(6 x 10⁻⁵ C)(5 x 10⁻⁵ C) / (5 x 10⁶ N)]
= √[(270 x 10⁻¹ Nm²) / (5 x 10⁶ N)]
= √(54 x 10⁻⁷ m²)
= √(5,4 x 10⁻⁶ m²) = 0,6√15 x 10⁻³ m = 0,6√15 mm
Nomor 2
Diketahui:
k = 9 x 10⁻⁹ Nm²/C², r = 12 cm & F = 3,3 x 10⁶ N
Ditanyakan:
q₁ = ... C dan q₂ = ... C
Jawab:
q₁ = q₂ = q
F = kq² / r²
q = r √(F / k)
= (1,2 x 10⁻¹ m) √[(3,3 x 10⁶ N) / (9 x 10⁹ Nm²/C²)]
= (1,2 x 10⁻¹ m) √(11/30 x 10⁻³ C²/m²)
= (1,2 x 10⁻¹ m) √(11/300 x 10⁻² C²/m²)
= (1,2 x 10⁻¹ m) (1/30 √33 x 10⁻¹ C/m)
= 0,04√33 x 10⁻² C
q₁ = q₂ = 0,04√33 x 10⁻² C