Question

Suatu benda P bermuatan listrik +4 x 10-⁹ C dan Q bermuatan -8 x 10-⁹ C terpisah sejauh 200 cm. Berapakah gaya tarik-menarik antara benda P dan Q jika k = 9 x 10° N m²/C²?​

Answer 1

Verified answer

Jawab:

besar gaya tarik menarik = 7,2 x [tex]10^{-8}[/tex] N

Penjelasan dengan langkah-langkah:

muatan listrik P = Q1 = +4 x [tex]10^{-9}[/tex] C

muatan listrik Q = Q2 = -8 x [tex]10^{-9}[/tex] C

jarak = r = 200 cm = 2m

k = 9 x [tex]10^{9}[/tex] [tex]Nm^{2} /C^{2}[/tex]

F = [tex]k\frac{Q1 . Q2}{r^{2} }[/tex]

F = 9 x [tex]10^{9}[/tex] [tex]Nm^{2} /C^{2}[/tex] x [tex]\frac{4 x 10^{-9 } C x 8 x 10^{-9} C }{2^{2}m^{2} }[/tex]

F = [tex]\frac{9 x 4 x 8}{4}[/tex] x [tex]10^{9+(-9)+(-9)}[/tex] N

F = 72 x [tex]10^{-9}[/tex] N = 7,2 x [tex]10^{-8}[/tex]