Respuesta:
[tex]c-5x\left(3+2x\right)=3\left(x+5\right)\quad :\quad x=-\frac{9+\sqrt{10c-69}}{10},\:x=-\frac{9-\sqrt{10c-69}}{10}[/tex]
Explicación paso a paso:
[tex]c-5x\left(3+2x\right)=3\left(x+5\right)[/tex]
[tex]c-15x-10x^2=3x+15[/tex]
[tex]c-15x-10x^2-15=3x+15-15[/tex]
[tex]c-15x-10x^2-15=3x[/tex]
[tex]c-15x-10x^2-15-3x=3x-3x[/tex]
[tex]-10x^2-18x+c-15=0[/tex]
[tex]x_{1,\:2}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(-10\right)\left(c-15\right)}}{2\left(-10\right)}[/tex]
[tex]x_{1,\:2}=\frac{-\left(-18\right)\pm \:2\sqrt{10c-69}}{2\left(-10\right)}[/tex]
[tex]x_1=\frac{-\left(-18\right)+2\sqrt{10c-69}}{2\left(-10\right)},\:x_2=\frac{-\left(-18\right)-2\sqrt{10c-69}}{2\left(-10\right)}[/tex]
[tex]x=-\frac{9+\sqrt{10c-69}}{10},\:x=-\frac{9-\sqrt{10c-69}}{10}[/tex]
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Verified answer
Respuesta:
[tex]c-5x\left(3+2x\right)=3\left(x+5\right)\quad :\quad x=-\frac{9+\sqrt{10c-69}}{10},\:x=-\frac{9-\sqrt{10c-69}}{10}[/tex]
Explicación paso a paso:
[tex]c-5x\left(3+2x\right)=3\left(x+5\right)[/tex]
[tex]c-15x-10x^2=3x+15[/tex]
[tex]c-15x-10x^2-15=3x+15-15[/tex]
[tex]c-15x-10x^2-15=3x[/tex]
[tex]c-15x-10x^2-15-3x=3x-3x[/tex]
[tex]-10x^2-18x+c-15=0[/tex]
[tex]x_{1,\:2}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(-10\right)\left(c-15\right)}}{2\left(-10\right)}[/tex]
[tex]x_{1,\:2}=\frac{-\left(-18\right)\pm \:2\sqrt{10c-69}}{2\left(-10\right)}[/tex]
[tex]x_1=\frac{-\left(-18\right)+2\sqrt{10c-69}}{2\left(-10\right)},\:x_2=\frac{-\left(-18\right)-2\sqrt{10c-69}}{2\left(-10\right)}[/tex]
[tex]x=-\frac{9+\sqrt{10c-69}}{10},\:x=-\frac{9-\sqrt{10c-69}}{10}[/tex]