Mol CH3OH = massa/Mr = 96/32 = 3
dH reaksi = mol x dHs
= 3 mol x - 297 kJ
= - 891 kj
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Mol CH3OH = massa/Mr = 96/32 = 3
dH reaksi = mol x dHs
= 3 mol x - 297 kJ
= - 891 kj
Tidak ada jawaban