Question

zadanie z matematyki

(-1/3)⁻¹-(-3)⁻¹-1/(-3)⁻¹+(-1)⁻¹/-3=

/- kreska ułamkowa

2⁻³/3⁻²÷4⁻³/9⁻¹=

2⁻²/2+1/2⁻²-(-1/2)⁻²+1⁻²/-2=

jeszcze jedno zadanie

tylko z dokładnymi obliczeniami proszę

Oblicz 150% wartości wyrażenia 8,4×10⁻⁸/2,1×10⁻⁶

i jeszcz jedno zadanie

a⁻³×a⁴÷a⁻¹/a⁻³÷a⁻⁵=

(1/x)⁻³÷x⁴/x⁻⁴÷(1/x)⁵×x⁻²=

a⁻⁵×b⁻⁴/x⁵×y⁻⁴÷a⁻⁸×x⁻³/b⁴×y⁵=

a⁻³b⁻⁴÷(a⁻²b⁻³)=

Answer 1

ZADANIE 1

(-1/3)⁻¹-(-3)⁻¹-1/(-3)⁻¹+(-1)⁻¹/-3=(-3)-(-1/3)-1/(-1/3)+(-1)/-3=

(-4)+1/3- 1*(-3)+1/3=(-4)+1/3+3+1/3=-1/3

 

2⁻³/3⁻²÷4⁻³/9⁻¹=(1/2)³*(1/3)² : (1/4)³/(1/9)=1/8*1/9 : 1/64*9=

1/72:9/64=1/72*64/9=64/648=16/162=8/81

 

2⁻²/2+1/2⁻²-(-1/2)⁻²+1⁻²/-2=(1/2)²/2+1/(1/2)²-(-2)²-1/2=1/4*1/2+1*4+4-1/2=

1/8+4+4-1/2=8 1/8-1/2=65/8-1/2=65/8-4/8=61/8=7 5/8

 

ZADANIE 2

Oblicz 150% wartości wyrażenia 8,4×10⁻⁸/2,1×10⁻⁶

8,4×10⁻⁸/2,1×10⁻⁶=

84/10*(1/10)⁸ / 21/10*(1/10)⁶=

84/10*1/100000000 / 21/10*1/1000000=84/1000000000 / 21/10000000=

84/1000000000*10000000/21=84/2100=21/525=3/75=1/25=0,04

 

100% -> 1/25

150% -> x

100x=1/25*150

100x=6

x=6/100=0,06

 

ZADANIE 3

a⁻³×a⁴÷a⁻¹/a⁻³÷a⁻⁵=a¹:a²:a⁻⁵=a⁻¹:a⁻⁵=a⁴

 

(1/x)⁻³÷x⁴/x⁻⁴÷(1/x)⁵×x⁻²=

x³:x⁴/x⁻⁴: 1/x⁵*1/x²=x³:x⁸: 1/x⁷=x⁻⁵: 1/x⁷=1/x⁵ : 1/x⁷=1/x⁻²=1/(1/x)²=

1/ 1/x²=1*x²=x²

 

 

a⁻⁵× b⁻⁴/x⁵× y⁻⁴÷a⁻⁸ × x⁻³/b⁴×y⁵=a⁻⁵* (1/b)⁴/x⁵ * y⁻⁴: a⁻⁸ * (1/x)³/b⁴xy⁵=

a⁻⁵* (1/b)⁴*(1/x)⁵ * y⁻⁴: a⁻⁸* (1/x)³*1/b⁴xy⁵=

a⁻⁵*1/b⁴*x⁵* y⁻⁴: a⁻⁸* 1/x³*1/b⁴xy⁵=a⁻⁵*1/b⁴*x⁵* y⁻⁴: a⁻⁸* 1/x³b⁴xy⁵=

a⁻⁵* 1/b⁴*x⁵*1/y⁴* 1/a⁸*1/x³b⁴xy⁵=a⁻⁵*1/a⁸*1/b⁴*x⁵*1/y⁴*1/x³b⁴xy⁵=

a⁻⁵:a⁸*1/b⁴*x⁵*1/y⁴*1/x³b⁴xy⁵=a⁻¹³*1/b⁴*x⁵*1/y⁴*1/x³b⁴xy⁵

 

a⁻³b⁻⁴÷(a⁻²b⁻³)=1/a³*1/b⁴:((1/a²*1/b³)=1/a³b⁴:1/a²b³=

1/a³b⁴*a²b³=a²b³/a³b⁴