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t segitiga= 672 : 42 = 16 cm
panjang FC = √34²-16² = 30
CE = AE= AC-FC = 42-30 = 12
Jadi, panjang CE 12 cm.
Labcd= L<adc+L<abc
672 cm^2 = 2(42xt)x1/2
672 cm^2=42 t
t=16
dc^2=df^2+fc^2
34^2=16^2+fc^2
fc=
fc=ae
jadi ec= 42-ae= 42-30=12 (a)