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⇒ k = √[(√3)²+(-1)²] = √4 = 2
⇒ tan α = a/b = -1/√3
α = -30
⇒kcos(2x-α) = 0
2cos(2x+30) = 0
cos(2x+30) = 0
⇔cos(2x+30) = cos90
2x + 30 = 90
2x = 60
x = 30
⇔cos(2x+30) = cos270
2x + 30 = 270
2x = 240
x = 120
⇔cos(2x+30) = cos450
2x+30 = 450
2x = 420
x = 210