Question

BUTUH BANTUAN!!!
tentukan:
1.Luas Daerah I
2.Luas daerah PQRS
3.Luas Daerah TUVW
​

Answer 1

Jawaban:

1. 63,5 m²

2.252 m²

3. 400 m²

Penjelasan dengan langkah-langkah:

Nomer 1

Luas PQRS

= p × l

= (12+6) × (8+6)

= 18 × 14

= 252 m²

Luas bangun D.

= s × s

= 6 × 6

= 36 m²

Luas bangun E

= p × l

= 12 × (6-4)

= 12 × 2

= 24 m²

Luas bangun C

= p × l

= 8 × 2

= 16 m²

Luas bangun B

= p × l

= 3,5 × 3

= 10,5 m²

Luas bangun A

= p × l

= 7,5 × 4

= 30 m²

Luas Daerah 1

= Luas PQRS - (Luas bangun D + Luas bangun E + Luas bangun C + Luas bangun B + Luas bangun A)

= 252 m² - (36 + 24 + 16 + 10,5 + 30)m²

= 252 m² - 116,5 m²

= [tex]\boxed{\sf 135,5\: {m}^{2}}[/tex]

[tex] \: [/tex]

Nomer 2

Luas PQRS

= p × l

= (12+6) × (8+2)

= 18 × 14

= [tex]\boxed{\sf 252\: {m}^{2}}[/tex]

[tex] \: [/tex]

Nomer 3

Luas TUVW

= p × l

= (4 + 6 + 8 + 2) × (12 + 6+ 2)

= 20 × 20

=[tex]\boxed{\sf 400\: {m}^{2}}[/tex]

[tex] \: [/tex]

[tex] \: [/tex]