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su consecutivo: x+1
x+1 + (x/2) = 13 + (x/5)+ (x+1)/11
mínimo común multiplo 110, multiplicas a ambos lados de la igualdad:
110(x+1) + 55x = 13×110 + 22x + 10(x+1)
110x + 110 + 55x = 1430 + 22x +10x +10
165x +110= 32x + 1440
165x -32x = 1440 -110
133x = 1330
x= 1330/133
x= 10
Los numeros son 10 y 11