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~(p ⇒ q) ≡ p ∧ ~q
Maka, untuk itu:
~[(p ∧ q) ⇒ r] ≡ (p ∧ q) ∧ ~r
Dengan berlaku komutatif, didapat:
~[(p ∧ q) ⇒ r] ≡ p ∧ (q ∧ ~r)