x-2y=11 [1]
x+5y=-17 [2]
Despejando x de [1]:
x=11+2y [3]
Sustituyendo [3] en [2]:
(11+2y)+5y=-17
Despejando para y:
11+2y+5y=-17
7y=-17-11=-28
y=-28/7
y=-4
Evaluando el valor de y en [3]:
x=11+2(-4)
x=11-8
x=3
=============================================
5x+y=-20 [1]
2x-3y=-8 [2]
Despejando x de [2]:
2x=-8+3y
x=(-8+3y)/2 [3]
Sustituyendo [3] en [1]:
5((-8+3y)/2)+y=-20
(-40+15y)/2+y=-20
((-40+15y)+2y)/2=-20
-40+15y+2y=-20*2=-40
-40+17y=-40
17y=-40+40=0
y=0/17
y=0
x=(-8+3(0))/2
x=(-8+0)/2
x=-8/2
x=-4
Los otros quedan de reto, si hay inconveniente en alguno pregunta.
1. x = 11 + 2y
11 + 2y + 5y = -17
11 + 7y = -17
7y = -28
y = -4
x = 3
2. y = -20 - 5x
2x - 3(-20 - 5x) = -8
2x + 60 + 15x = -8
17x = -68
x = -4
y = 0
3. b = 1 - 2a
-6a - 5(1-2a) = -9
-6a - 5 + 10a = -9
4a = -4
a = -1
b = 3
4. 2v = -5 - 7u
v = -5 - 7u / 2
-35u - 10(-5 - 7u / 2) = -25
-35u - 5(-5 - 7u) = -25
-35u + 25 + 35u = -25
???
5. x = -17 + 2y
-17 + 2y + 5y = -17
7y = 0
x= -17
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x-2y=11 [1]
x+5y=-17 [2]
Despejando x de [1]:
x=11+2y [3]
Sustituyendo [3] en [2]:
(11+2y)+5y=-17
Despejando para y:
11+2y+5y=-17
7y=-17-11=-28
y=-28/7
y=-4
Evaluando el valor de y en [3]:
x=11+2(-4)
x=11-8
x=3
=============================================
5x+y=-20 [1]
2x-3y=-8 [2]
Despejando x de [2]:
2x=-8+3y
x=(-8+3y)/2 [3]
Sustituyendo [3] en [1]:
5((-8+3y)/2)+y=-20
Despejando para y:
(-40+15y)/2+y=-20
((-40+15y)+2y)/2=-20
-40+15y+2y=-20*2=-40
-40+17y=-40
17y=-40+40=0
y=0/17
y=0
Evaluando el valor de y en [3]:
x=(-8+3(0))/2
x=(-8+0)/2
x=-8/2
x=-4
Los otros quedan de reto, si hay inconveniente en alguno pregunta.
1. x = 11 + 2y
11 + 2y + 5y = -17
11 + 7y = -17
7y = -28
y = -4
x = 3
2. y = -20 - 5x
2x - 3(-20 - 5x) = -8
2x + 60 + 15x = -8
17x = -68
x = -4
y = 0
3. b = 1 - 2a
-6a - 5(1-2a) = -9
-6a - 5 + 10a = -9
4a = -4
a = -1
b = 3
4. 2v = -5 - 7u
v = -5 - 7u / 2
-35u - 10(-5 - 7u / 2) = -25
-35u - 5(-5 - 7u) = -25
-35u + 25 + 35u = -25
???
5. x = -17 + 2y
-17 + 2y + 5y = -17
7y = 0
y = 0
x= -17