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g = gula
Bu Sofi = 6b + 5g = 103000 | x1 | 6b + 5g = 103000
Bu Ratna = 2b + g = 27000 | x5 | 10b + 5g = 135000 -
-4b = -32000
b = -32000/-4 = 8000
2b + g = 27000
2(8000) + g = 27000
16000 + g = 27000
g = 27000 - 16000 = 11000
Bu Endah = 4b + 3g
= 4(8000) + 3(11000)
= 32000 + 33000
= 65000
Jadi, yang harus dibayar Bu Endah = Rp 65.000
maaf kalo salah....
gula = y
menggunakan cara eliminasi-substitusi
(6x + 5y = 103.000) x 1
(2x + y = 27.000) x 3
menjadi:
6x + 5y = 103.000
6x + 3y = 81.000
----------------------- (-)
2y = 22.000
y = 22.000 : 2 = 11.000
trs menggunakan substitusi. masukkan y ke salah satu rumus diatas (yg blm dikalikan)
2x + y = 27.000
2x + 11.000 = 27.000
2x = 27.000 - 11.000
2x = 16.000
x = 16.000 : 2 = 8.000
ditanya:
4x + 3y = ?
(4 x 8.000) + (3 x 11.000)
32.000 + 33.000 = 65.000