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2pl + 2pt + 2lt
= 2×20×15 + 2×20×10 + 2×15×10
= 600 + 400 + 300
= 1.300 cm²
tripleks: 50×30 cm
= 1500 cm²
sisa: 1500-1300
= 200 cm²
maaf ada ralat
Ukuran Balok → p = 20 cm.l = 15 cm.t = 10 cm
Ukuran Tripleks → 50 cm × 30 cm
≡ Ditanya: Luas Sisa Tripleks?
≡ Dijawab:
⇔ Tentukan dulu luas permukaan balok (Lp):
Lp = 2 × [(p × l) + (p × t) + (l × t)]
Lp = 2 × [(20 × 15) + (20 × 10) + (15 × 10)]
Lp = 2 × 650
Lp = 1.300 cm²
⇔ Tentukan sisa tripleks:
Sisa = (50 × 30) - 1.300 cm²
Sisa = 1.500 - 1.300
Sisa = 200 cm²
∴ Jadi, sisa luas tripleksnya adalah 200 cm²