Odpowiedź:
Szczegółowe wyjaśnienie:
Z2/
m ∈ (3; +∞)
=> m-3 > 0 ∧ m+4 > 0
|m-3| = m-3 ∧ |m+4| = m+4
L = m - 3 - m - 4 = -7 = const
c.n.w.
Z3/
A) |m+5| ≤ 3
B) |x-11| = 2
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Odpowiedź:
Szczegółowe wyjaśnienie:
Z2/
m ∈ (3; +∞)
=> m-3 > 0 ∧ m+4 > 0
|m-3| = m-3 ∧ |m+4| = m+4
L = m - 3 - m - 4 = -7 = const
c.n.w.
Z3/
A) |m+5| ≤ 3
B) |x-11| = 2