Jawab:
logarima
sifat
i) ᵃlog a = 1
ii) ᵃlog x. ˣlog a = ᵃlog a = 1
Penjelasan dengan langkah-langkah:
dari baris ketiga
[( 3.³log 2 . ²log 3 + 4. ³log 3 ) / ( 6. ²log 2 - 3 ²log 2) ]² =
.
karena ³log 2 . ²log 3 = ³log3 = 1
dan ²log2 = 1 maka
= [{ 3.³log 3 + 4. ³log 3 } / { 6. ²log 2 - 3 ²log 2 } ]²
= [ {3 (1) + 4 (1) } / { 6 (1) - 3 (1) }]²
= [ (3 + 4) / (6- 3)]²
= (7 /3)²
= 49/9
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Jawab:
logarima
sifat
i) ᵃlog a = 1
ii) ᵃlog x. ˣlog a = ᵃlog a = 1
Penjelasan dengan langkah-langkah:
dari baris ketiga
[( 3.³log 2 . ²log 3 + 4. ³log 3 ) / ( 6. ²log 2 - 3 ²log 2) ]² =
.
karena ³log 2 . ²log 3 = ³log3 = 1
dan ²log2 = 1 maka
.
= [{ 3.³log 3 + 4. ³log 3 } / { 6. ²log 2 - 3 ²log 2 } ]²
= [ {3 (1) + 4 (1) } / { 6 (1) - 3 (1) }]²
= [ (3 + 4) / (6- 3)]²
= (7 /3)²
= 49/9