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= (2^24 - 1)(2^24 + 1)
= (2^12 - 1)(2^12 + 1)(2^24 + 1)
= (2^6 - 1)(2^6 + 1)(2^12 + 1)(2^24 + 1)
= (64 - 1)(64 + 1)(2^12 + 1)(2^24 + 1)
= 63.65.(2^12 + 1)(2^24 + 1)
* Digit terakhir dari 2^48=2^4=6..jadi digit terakhir 2^48-1=6-1=5 jadi kmungkinan bisa dibagi 63 dan 65