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N M = n X Na = 0,1665 X 6,02X = 1X
M + 2HCl → MCl₂ + H₂
mol H₂ = Volume/STP
= 3,73/22,4
= 0,1665 mol
mol M = koef M/koef H₂ x mol H₂
= 1/1 x 0,1665
= 0,1665 mol
JP M = mol x Bilangan avogadro
= 0,1665 x 6,02 x 10²³
= 1 x 10²³
Jadi, jumlah partikel logam M yang bereaksi adalah 1 x 10²³ partikel (Jawaban D)