cos A + cos B = 2 . cos ((A + B)/2) . cos ((A - B)/2) cos A + cos B = 2 . cos (270°/2) . cos ((270° - 2B)/2) cos A + cos B = 2 . cos 135° . cos (135° - B) cos A + cos B = 2 . (-1/2 √2) . (cos 135° cos B + sin 135° . sin B) cos A + cos B = -√2 . (-1/2 √2 . cos B + 1/2√2 . sin B) cos A + cos B = cos B - sin B
A + B = 270° B = 270° - A cos B = cos (270° - A) cos B = cos 270° . cos A + sin 270° . sin A cos B = 0 + (-1) , sin A cos B = - sin A
sin B = sin (270° - A) sin B = sin 270° . cos A - cos 270° . sin A sin B = (-1) . cos A - 0 sin B = - cos A
cos A + cos B = - sin A - sin B atau cos A + cos B = cos A - (- cos A) cos A + cos B = 2 cos A
Verified answer
Bab TrigonometriMatematika SMA Kelas X
A + B = 270°
A = 270° - B
A - B = 270° - B - B = 270° - 2B
cos A + cos B = 2 . cos ((A + B)/2) . cos ((A - B)/2)
cos A + cos B = 2 . cos (270°/2) . cos ((270° - 2B)/2)
cos A + cos B = 2 . cos 135° . cos (135° - B)
cos A + cos B = 2 . (-1/2 √2) . (cos 135° cos B + sin 135° . sin B)
cos A + cos B = -√2 . (-1/2 √2 . cos B + 1/2√2 . sin B)
cos A + cos B = cos B - sin B
A + B = 270°
B = 270° - A
cos B = cos (270° - A)
cos B = cos 270° . cos A + sin 270° . sin A
cos B = 0 + (-1) , sin A
cos B = - sin A
sin B = sin (270° - A)
sin B = sin 270° . cos A - cos 270° . sin A
sin B = (-1) . cos A - 0
sin B = - cos A
cos A + cos B = - sin A - sin B
atau
cos A + cos B = cos A - (- cos A)
cos A + cos B = 2 cos A