Question

Bil kompleks
z 1 = 2 ( cos 60 + i sin 60 ) dan z 2 = 3 ( cos 30 + i sin 30 )
tentukan
z1 - z2

Answer 1

Z₁ = 2 [1/2 + (√3/2)i] = 1 + i√3

Z₂ = 3 [(√3/2) + (1/2)i] = (3√3)/2 + (3/2)i

Z₁ - Z₂ = [1 - (3√3)/2] + [√3 - 3/2] i

Atau,

Z₁ - Z₂ = 1/2.[(2 - 3√3) + (2√3 - 3) i]