Jawab:
[tex]128^{\frac{3}{7} } =(2^{2} )^{\frac{3}{7} } = 2^{(2)(\frac{3}{7}) } =2^{3}=8[/tex]
[tex]81^{\frac{1}{4} } -64^{\frac{1}{6} } =(3^{4})^{\frac{1}{4} } -(2^{6} )^{\frac{1}{6} } =3^{(4)(\frac{1}{4}) }- 2^{(6)(\frac{1}{6}) }=3^1-2^1=3-2=1[/tex]
[tex](2^{3} *3^{-2} )^{-1}= 2^{(3)(-1)} *3^{(-2)(-1)} =2^{-3}*3^{2} =\frac{3^2}{2^3} =\frac{9}{8}[/tex]
[tex](16^{\frac{2}{3} } )^{-\frac{3}{4} } =16^{(\frac{2}{3} )(-\frac{3}{4} )} =16^{-\frac{1}{2} }=(4^2) ^{-\frac{1}{2} }=4^{(2)(-\frac{1}{2} )}=4^{-1} =\frac{1}{4}[/tex]
Semoga dapat membantu :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawab:
[tex]128^{\frac{3}{7} } =(2^{2} )^{\frac{3}{7} } = 2^{(2)(\frac{3}{7}) } =2^{3}=8[/tex]
[tex]81^{\frac{1}{4} } -64^{\frac{1}{6} } =(3^{4})^{\frac{1}{4} } -(2^{6} )^{\frac{1}{6} } =3^{(4)(\frac{1}{4}) }- 2^{(6)(\frac{1}{6}) }=3^1-2^1=3-2=1[/tex]
[tex](2^{3} *3^{-2} )^{-1}= 2^{(3)(-1)} *3^{(-2)(-1)} =2^{-3}*3^{2} =\frac{3^2}{2^3} =\frac{9}{8}[/tex]
[tex](16^{\frac{2}{3} } )^{-\frac{3}{4} } =16^{(\frac{2}{3} )(-\frac{3}{4} )} =16^{-\frac{1}{2} }=(4^2) ^{-\frac{1}{2} }=4^{(2)(-\frac{1}{2} )}=4^{-1} =\frac{1}{4}[/tex]
Semoga dapat membantu :)