5dregensleyer
A = ( 32-20)/2 = 12/2 = 6 s = (72-32-20)/2 = 20/2 = 10 t = √10² - 6² = √ 100-36 = √ 64 = 8 luas trapesium Luas = (a+b) x t/2 = ( 32+20) x 8/2 = 52 x 4 = 208 cm²
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InesNisa
32+20= 52. 72-52= 20. 20:2= 10. Jadi sisi bagian samping masing masing 10 cm. 32-20 = 12. 12:2= 6. Pythagoras 10² - 6² = 64 = 8 cm. Luas= ½ x (20+32) x 8 = 208 (D)
= 12/2
= 6
s = (72-32-20)/2
= 20/2
= 10
t = √10² - 6²
= √ 100-36
= √ 64
= 8
luas trapesium
Luas = (a+b) x t/2
= ( 32+20) x 8/2
= 52 x 4
= 208 cm²