Question

Beserta caranya.. ∫cos6x.sin3x dx trims

Answer 1

∫ cos 6x sin 3x dx = 1/2 ∫ 2 cos 6x sin 3x dx
= 1/2 ∫ (sin 9x - sin 3x) dx
= ∫ 1/2 sin 9x dx - ∫1/2 sin 3x dx
= 1/2 (1/9) (- cos 9x) - 1/2 (1/3)(-cos 3x ) 
= - 1/18 cos 9x + 1/6 cos 3x +c
= -1/18 ( cos 9x - 3 cos 3x) + c