berapakah volume dari kerucut dengan jari-jari alas 21cm dan panjang garis pelukis adalah 29cm
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Materi : Bangun Ruang Sisi Lengkung
Tinggi Kerucut
t² = s² - r²
t² = 29² - 21²
t² = 400
t = √400
t = 20 cm
Volume Kerucut
V = ⅓ × π × r² × t
V = ⅓ × 22/7 × 21 cm × 21 cm × 20 cm
V = 22 × 21 cm² × 20 cm
V = 462 cm² × 20 cm
V = 9.240 cm³
Semoga bisa membantu
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T = √29² - 21²
= √(29(29) - (21(21)
= √841 - 441
= √400
= √20²
= 20 CM
V = (1/3(22/7(21²(20)
= (1/3(22/7(441(20)
= (1/3(22/7(8.820)
= (1/3(22(8.820/7)
= (1/3(22(1.260)
= (1/3(27.720)
= 27.720/3
= 9.240 CM³