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Verified answer
Resultan Vektor.F₁ₓ = F₁ cos 60° = (3 N)(1/2) = 1,5 N
F₂ₓ = F₂ = 3 N
F₃ₓ = F₃ cos 60 = (5 N)(1/2) = 2,5 N
ΣFₓ = 7 N
F₁y = F₁ sin 60° = (3 N)(1/2 √3) = 1,5√3 N
F₂y = 0 N
F₃y = F₃ sin 60° = (5 N)(1/2 √3) = 2,5√3 N
ΣFy = 4 N
R = √(ΣFₓ² + ΣFy²)
= √[(7 N)² + (4 N)²]
= √65 N