f''(x) = 4 - 6x
f'(x) = 4x - 3x² + C
f'(2) = 4(2) - 3(2)² + C
-4 = 8 - 12 + C
-4 = -4 + C
C = 0
f'(x) = 4x - 3x²
f(x) = 2x² - x³ + C
f(2) = 2(2)² - 2³ + C
7 = 8 - 8 + C
C = 7
jadi f(x) = 2x² - x³ + 7
= -x³ + 2x² + 7
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maaf kalau ada kesalahan
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f''(x) = 4 - 6x
f'(x) = 4x - 3x² + C
f'(2) = 4(2) - 3(2)² + C
-4 = 8 - 12 + C
-4 = -4 + C
C = 0
f'(x) = 4x - 3x²
f(x) = 2x² - x³ + C
f(2) = 2(2)² - 2³ + C
7 = 8 - 8 + C
C = 7
jadi f(x) = 2x² - x³ + 7
= -x³ + 2x² + 7
semoga membantu
maaf kalau ada kesalahan