∫ (x-1) (x+3) dx
= ∫ x² + 3x - x - 3 dx
= ∫ x² + 2x - 3 dx
= 1/3 x³ + 2/2 x² - 3/1 x
= 1/3 x³ + x² - 3x
slngkpny ad d lmprn.
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
∫ (x-1) (x+3) dx
= ∫ x² + 3x - x - 3 dx
= ∫ x² + 2x - 3 dx
= 1/3 x³ + 2/2 x² - 3/1 x
= 1/3 x³ + x² - 3x
slngkpny ad d lmprn.