Question

Berapakah biloks masing-masng senyawa atau ion berikut? dengan cara!
a. Na2S2O3
b. Ca(OCl)2
c. NaIO
d. CrO4 2-
e. NaH2PO4
f. XeO4 2-

Answer 1

A.Na2S2O3➡2×biloks Na + 2×biloks S + 3×biloks O=0
(2×1) + S + (3× -2)=0
2 + S -6 = 0
S -4=0
S= +4

b.Ca(OCl)2 ➡1×biliks Ca + 2×biloks O + 2×biloks Cl=0
(1×2) + (2×-2) + 2Cl = 0
2 -4 + 2Cl =0
-2 + 2Cl =0
2Cl = +2
Cl= 2/2
Cl=+1

c.NalO➡1×biloks Na + 1×biloks l + 1×biloks O=0
(1×1) + l + (1× -2)=0
1 + I -2 =0
I -1 =0
I= +1

d.CrO4^2-➡1×biloks Cr + 4×biloks O= -2
Cr + (4× -2)=-2
Cr -8= -2
Cr= -2 + 8
Cr = +6

e.NaH2PO4➡1×biloks Na + 2×biloks H + 1×biloks P + 4×biloks O=0
(1×1) + (2×1) + P + (4× -2)= 0
1 + 2 + P-8 = 0
3 + P - 8 = 0
P - 5=0
P= +5

f.XeO4^2-➡1×biloks Xe + 4×biloks O =-2
Xe + (4× -2)= -2
Xe -8= -2
Xe = -2 + 8
Xe = +6