Jawaban:
Penjelasan:
Diketahui:
=> Resistansi (R) = 450 Ohm
=> Panjang (l) = 1,5 m
=> Luas penampang (A) = [tex]3mm^2[/tex] = [tex]3 \times 10^{-6}\ m^2[/tex]
Ditanya:
Hambatan jenis ([tex]\rho[/tex]) ?
Jawab:
[tex]= > R = \rho \times \frac{l}{A}\\= > 450 = \rho \times \frac{1,5}{3 \times 10^{-6}}\\= > \rho = \frac{450}{\frac{1,5}{3 \times 10^{-6}}} \\= > \rho = \frac{450 \times 3 \times 10^{-6}}{1,5} \\= > \rho = \frac{1350 \times 10^{-6}}{1,5} \\= > \rho = 900 \times 10^{-6}\\= > \rho = 9 \times 10^{-4}\ \Omega m[/tex]
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Jawaban:
Penjelasan:
Diketahui:
=> Resistansi (R) = 450 Ohm
=> Panjang (l) = 1,5 m
=> Luas penampang (A) = [tex]3mm^2[/tex] = [tex]3 \times 10^{-6}\ m^2[/tex]
Ditanya:
Hambatan jenis ([tex]\rho[/tex]) ?
Jawab:
[tex]= > R = \rho \times \frac{l}{A}\\= > 450 = \rho \times \frac{1,5}{3 \times 10^{-6}}\\= > \rho = \frac{450}{\frac{1,5}{3 \times 10^{-6}}} \\= > \rho = \frac{450 \times 3 \times 10^{-6}}{1,5} \\= > \rho = \frac{1350 \times 10^{-6}}{1,5} \\= > \rho = 900 \times 10^{-6}\\= > \rho = 9 \times 10^{-4}\ \Omega m[/tex]