Question

Berapa volume (L) 6.4 gram gas metana (CH4) jika pada keadaan sama 1 L gas nitrogen memiliki massa 1.4 gram? Diketahui Ar N = 14, Ar C = 12 dan Ar H= 1

Answer 1

Dik :
• m CH4 = 6,4 gram
• V N2 = 1 L
• m N2 = 1,4 gram

dit :
V CH4 ?

Mr CH4 = 12 + 4 = 16
n CH4 = 6,4 gr / 16 = 0,4 mol
Mr N2 = 28
n N2 = 1,4 gr / 28 = 0,05 mol
n N2 / V N2 = n CH4 / V CH4
V CH 4 = n CH4 × V N2 / n N2
= 0,4 × 1 / 0,05 = 8 L