Question

Berapa tetapan hidrolisis dan pH larutan CH3COONa 0,1 M jika diketahui Ka CH3COOH =1,8 × 10^-5

Answer 1

Kh (tetapan hidrolisis) = Kw/Ka = 10^-14/1,8x10^-5 = 5,56 x 10^-8

[OH-] = sqrt(Kh x M)
= sqrt(5,56 x 10^-8 x 10^-1)
= sqrt( 55,6 x 10^-10)
= 7,46 x 10^-5

pOH = 5 - log 7,46
pH = 9 + log 7,46