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Matematika SMA Kelas XI
[1]
Gunakan pemfaktoran a³ - b³ = (a - b)(a² + ab + b²)
Yang dapat menjadi a - b = (∛a - ∛b)(∛a² + ∛(ab) + ∛b²)
Sehingga,
⇔ Lim [x - 8] / [∛x - 2]
x → 8
⇔ Lim [ (∛x - ∛8)(∛x² + ∛(8x) + ∛8²)] / [∛x - 2]
x → 8
⇔ Lim [ ∛x² + ∛(8x) + ∛8² ]
x → 8
= ∛8² + ∛(8.8) + ∛64
= 3[∛64]
= 3(4)
= 12
[2]
Dengan cara yang sama seperti no.1
⇔ Lim [x - 1] / [∛x - 1]
x → 1
⇔ Lim [ (∛x - ∛1)(∛x² + ∛(1.x) + ∛1²)] / [∛x - 1]
x → 1
⇔ Lim [ ∛x² + ∛(1.x) + ∛1² ]
x → 1
= 1 + 1 + 1
= 3