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Verified answer
MAPEL = MATEMATIKAKELAS = 8
BAB = PEMFAKTORAN ALJABAR
diketahui=
luas persegi panjang = (20x²-27x-14)
x = 3
ditanya =
kll persegi panjang??
L. persegi panjang = pemfaktoran dari 20x²-27x-14)
faktor nya
20x² -27x -14
(4x + 7)(5x - 2)
-8x + 35x = -27
faktornya = (4x + 7)(5x - 2)
berarti sisi sisi nya
panjnag = (4x + 7)
lebar = (5x - 2)
kll persegi panjang = 2(P+L)
= 2(4x + 7 +5x - 2)
= 2(9x + 5)
= 18x + 10
jika x = 3 maka kelilingnya
= 18x + 10
= 18(3) + 10
= 54 + 10
= 64
semoga membantu