Question

Berapa ia harus membayar?

Answer 1

Beras = x, minyak goreng = y, mie = z
paket a = 3x + 2y + 5z = 58500
paket b = 2x + 3y + 10z = 69000
paket c = 2x + y + 5z = 37500

3x + 2y + 5z = 58500
2x + y + 5z = 37500
-------------------------------- ( - )
x + y = 21000 ......... ( i )

3x + 2y + 5z = 58500 |x2| 6x + 4y + 10z = 117000
2x + 3y + 10z = 69000 |x1| 2x + 3y + 10z = 69000
                                 --------------------------------- ( - )
                                       4x + y = 48000 ........( ii )

4x + y = 48000
x + y = 21000 
--------------------- ( - )
3x = 27000
x = 27000/3
x = 9000

3(9000) + 2y + 5z = 58500
27000 + 2y + 5z = 58500
2y + 5z = 58500 - 27000
2y + 5z = 31500 ...... ( iii )

2(9000) + y + 5z = 37500
18000 + y + 5z = 37500
y + 5z = 37500 - 18000
y + 5z = 19500 ..... ( iv )

2y + 5z = 31500
y + 5z = 19500
------------------------ ( - )
y = 12000

2(9000) + 12000 + 5z = 37500
18000 + 12000 + 5z = 37500
5z = 37500 - 18000 - 12000
5z = 7500
z = 7500/5
z = 1500

jadi, harga 1kg beras = Rp. 9000, 1L minyak goreng = Rp. 12000, 1 mie instans = Rp. 1500

Pertanyaannya, ibu tami membeli 1L minyak goreng, berapa bu tami harus membayar..
4. Rp. 12000

Answer 2

Jdi yg hrus ia byar adalah Rp.12.000.00