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Turunkan Integralkan
4x + (x - 1)²
4 - 1/3(x - 1)³
0 + 1/12(x-1)^4
Soal = 4x{(1/3)(x-1)³ - 4(1/12(x-1)^4) batas atas 3 dan batas bawah 0
= {(4x/3)(x-1)³ - (1/3)(x-1)^4} batas atas 3 dan batas bawah 0
= {(12/3(3-1)³ - (1/3)(3-1)^4} - {(4/3)(0-1)³ - (1/3)(0-1)^4}
= { 4(8) - (1/3)(16)} - ((4/3)(-1) - (1/3)(1)}
= 32 - 16/3 + 4/3 + 1/3
= 96/3 - 11/3
= 85/3 delapan puluh lima per tiga atau dua puluh delapan 1/3