Question

Berapa gram zat terlarut yg terdpt dlm 1 mL CaCl2 0,5 M, 100mL Ca(OH)2 0,4 M dan 10 mL KNO3 0,2 M?

Answer 1

1 mL CaCl₂ 0,5 M → 0,5 mmol CaCl₂
massa = mol × Mr
   = (0,5)(111)
   = 55,5 mg


100mL Ca(OH)₂ 0,4 M → 40 mmol Ca(OH)₂
massa = mol × Mr
   = (40)(74)
   = 2960 mg
   = 2,96 g


10 mL KNO₃ 0,2 M → 5 mmol KNO₃
massa = mol × Mr
   = (5)(101)
   = 505 mg


SOLVED!