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kalo ia,
(x^2-3x+3)(x+p)=x^3-qx......
x^3-(3-p)x^2+(2-3p)x+2p= x^3-qx......
trus pindahin ke sebelah, jd
x^3-(3-p)x^2+(2-3p)x+2p-(x^3-qx^2+x+6)=0
(-3+p+q)x^2-(1-3p)x+2p-6
tp coba perhatikan lg + - mungkin ada yg salah