Bentuk cos (x-70)= sin(2x+10) dipenuhi oleh nilai x = .... plis bantu
whongaliemcos (x - 70) = sin (2x + 10) = cos ( 90 - (2x + 10)) = cos (90 - 2x - 10) cos (x- 70) = cos (80 - 2x) x - 70 = 80 - 2x x + 2x = 80 + 70 3x = 150 x = 150 : 3 x = x = 50 + k .360 atau x = - 50 + k.360 untuk k = 1 ----> x = 50 + 1 .360 atau x = - 50 + 360 x = 50 + 360 x = - 50 + 360 x = x =
= cos ( 90 - (2x + 10))
= cos (90 - 2x - 10)
cos (x- 70) = cos (80 - 2x)
x - 70 = 80 - 2x
x + 2x = 80 + 70
3x = 150
x = 150 : 3
x =
x = 50 + k .360 atau x = - 50 + k.360
untuk k = 1 ----> x = 50 + 1 .360 atau x = - 50 + 360
x = 50 + 360 x = - 50 + 360
x = x =