Question

Benda tingginya 5 cm terletak 30 cm di depan lensa cembung.jika jarak bayangan 60 cm,maka hitunglah jarak titik fokus lensa,perbesaran lensa,tinggi bayangan,dan daya lensa

Answer 1

Dik :
ho = 5 cm
so = 30 cm
si = 60 cm

Dit : f, M, hi, dan P
Jawab :
1/f = 1/so + 1/si
1/f = 1/30 + 1/60
1/f = 2/60 + 1/60
1/f = 3/60
f = 60/3 = 20 cm

M = si/so
M = 60/30
M = 2

hi = M . ho
hi = 2 . 5
hi = 10 cm

P = 1/f
P = 1/20
P = 0,05 dioptri