Benda tinggi 10 cm diletakkan didepan cermin cekung yang titik fokusnya 15 cm. jika jarak benda dari cermin 20 cm,tentukan jarak bayangan dari cermin dan perbesaran bayangan
GalladeavieroDiketahui h = 10 cm f = 15 cm s = 20 cm
Ditanya s' dan M ?
Jawab 1/f =1/s + 1/s' 1/15 =1/20+1/s' 1/s' = 1/15-1/20 1/s' = 1/60 s' = 60 cm <------Jarak bayangan
M = s'/s M = 60/20 M = 3 kali <-------Perbesaran bayangan
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MuhammadFadhilah
1/f = 1/si +1/so 1/15 = 1/20 + 1/so 1/so = 1/15 - 1/20 =1/60 so = 60 cm so= jarak bayangan ke cermin perbesaran = M M= si/so =20 / 30 =0,6 kali
h = 10 cm
f = 15 cm
s = 20 cm
Ditanya s' dan M ?
Jawab
1/f =1/s + 1/s'
1/15 =1/20+1/s'
1/s' = 1/15-1/20
1/s' = 1/60
s' = 60 cm <------Jarak bayangan
M = s'/s
M = 60/20
M = 3 kali <-------Perbesaran bayangan
1/15 = 1/20 + 1/so
1/so = 1/15 - 1/20
=1/60
so = 60 cm
so= jarak bayangan ke cermin
perbesaran = M
M= si/so
=20 / 30
=0,6 kali